Base | Representation |
---|---|
bin | 11001000011101110… |
… | …10010101101000111 |
3 | 1021201120021110202022 |
4 | 30201313102231013 |
5 | 210022434411201 |
6 | 10102533233355 |
7 | 654243664142 |
oct | 144167225507 |
9 | 37646243668 |
10 | 13453044551 |
11 | 5783990541 |
12 | 273549285b |
13 | 13651c63bb |
14 | 9189bb059 |
15 | 53b0e241b |
hex | 321dd2b47 |
13453044551 has 4 divisors (see below), whose sum is σ = 13533601872. Its totient is φ = 13372487232.
The previous prime is 13453044511. The next prime is 13453044559. The reversal of 13453044551 is 15544035431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15544035431 = 2731 ⋅5691701.
It is a cyclic number.
It is not a de Polignac number, because 13453044551 - 218 = 13452782407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13453044559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40278410 + ... + 40278743.
It is an arithmetic number, because the mean of its divisors is an integer number (3383400468).
Almost surely, 213453044551 is an apocalyptic number.
13453044551 is a deficient number, since it is larger than the sum of its proper divisors (80557321).
13453044551 is an equidigital number, since it uses as much as digits as its factorization.
13453044551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80557320.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 13453044551 its reverse (15544035431), we get a palindrome (28997079982).
The spelling of 13453044551 in words is "thirteen billion, four hundred fifty-three million, forty-four thousand, five hundred fifty-one".
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