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1345442250539 = 1759764890421
BaseRepresentation
bin10011100101000010100…
…110110111111100101011
311202121211011221221222102
4103211002212313330223
5134020431204004124
62510030532444015
7166130212302002
oct23450246677453
94677734857872
101345442250539
11479665090652
12198909a7960b
1399b4a820b9a
1449196859c39
1524ee85c0aae
hex139429b7f2b

1345442250539 has 4 divisors (see below), whose sum is σ = 1346207142720. Its totient is φ = 1344677358360.

The previous prime is 1345442250521. The next prime is 1345442250541. The reversal of 1345442250539 is 9350522445431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1345442250539 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1345442250493 and 1345442250502.

It is not an unprimeable number, because it can be changed into a prime (1345442250569) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 382443452 + ... + 382446969.

It is an arithmetic number, because the mean of its divisors is an integer number (336551785680).

Almost surely, 21345442250539 is an apocalyptic number.

1345442250539 is a deficient number, since it is larger than the sum of its proper divisors (764892181).

1345442250539 is an equidigital number, since it uses as much as digits as its factorization.

1345442250539 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 764892180.

The product of its (nonzero) digits is 2592000, while the sum is 47.

The spelling of 1345442250539 in words is "one trillion, three hundred forty-five billion, four hundred forty-two million, two hundred fifty thousand, five hundred thirty-nine".

Divisors: 1 1759 764890421 1345442250539