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134551265443051 = 532538703121567
BaseRepresentation
bin11110100101111110101000…
…011000010111110011101011
3122122101222100000220001002111
4132211332220120113303223
5120113441442423134201
61154055555323343151
740225002534522322
oct3645765030276353
9578358300801074
10134551265443051
1139965964664446
1213110b2a681ab7
135a1018c497172
14253245d1390b9
151084ec1b92b51
hex7a5fa8617ceb

134551265443051 has 4 divisors (see below), whose sum is σ = 137089968564672. Its totient is φ = 132012562321432.

The previous prime is 134551265443039. The next prime is 134551265443073. The reversal of 134551265443051 is 150344562155431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134551265443051 - 215 = 134551265410283 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134551265442986 and 134551265443004.

It is not an unprimeable number, because it can be changed into a prime (134551265443081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1269351560731 + ... + 1269351560836.

It is an arithmetic number, because the mean of its divisors is an integer number (34272492141168).

Almost surely, 2134551265443051 is an apocalyptic number.

134551265443051 is a deficient number, since it is larger than the sum of its proper divisors (2538703121621).

134551265443051 is an equidigital number, since it uses as much as digits as its factorization.

134551265443051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2538703121620.

The product of its (nonzero) digits is 4320000, while the sum is 49.

The spelling of 134551265443051 in words is "one hundred thirty-four trillion, five hundred fifty-one billion, two hundred sixty-five million, four hundred forty-three thousand, fifty-one".

Divisors: 1 53 2538703121567 134551265443051