1345514113411 has 4 divisors (see below), whose sum is σ = 1449015199072. Its totient is φ = 1242013027752.

The previous prime is 1345514113369. The next prime is 1345514113417. The reversal of 1345514113411 is 1143114155431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1345514113411 - 2¹⁵ = 1345514080643 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1345514113417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51750542811 + ... + 51750542836.

It is an arithmetic number, because the mean of its divisors is an integer number (362253799768).

Almost surely, 2^{1345514113411} is an apocalyptic number.

1345514113411 is a deficient number, since it is larger than the sum of its proper divisors (103501085661).

1345514113411 is a wasteful number, since it uses less digits than its factorization.

1345514113411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103501085660.

The product of its digits is 14400, while the sum is 34.

Adding to 1345514113411 its reverse (1143114155431), we get a palindrome (2488628268842).

The spelling of 1345514113411 in words is "one trillion, three hundred forty-five billion, five hundred fourteen million, one hundred thirteen thousand, four hundred eleven".