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1345514534213 = 7917031829547
BaseRepresentation
bin10011100101000110111…
…010100111010101000101
311202122000012222100112112
4103211012322213111011
5134021103210043323
62510042034030405
7166132050556403
oct23450672472505
94678005870475
101345514534213
114796a1971423
1219892a118405
1399b5c7abca5
14491a22b4473
1524eeeaed178
hex13946ea7545

1345514534213 has 4 divisors (see below), whose sum is σ = 1362546363840. Its totient is φ = 1328482704588.

The previous prime is 1345514534207. The next prime is 1345514534257. The reversal of 1345514534213 is 3124354155431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1345514534213 - 212 = 1345514530117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1345514534513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8515914695 + ... + 8515914852.

It is an arithmetic number, because the mean of its divisors is an integer number (340636590960).

Almost surely, 21345514534213 is an apocalyptic number.

It is an amenable number.

1345514534213 is a deficient number, since it is larger than the sum of its proper divisors (17031829627).

1345514534213 is an equidigital number, since it uses as much as digits as its factorization.

1345514534213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17031829626.

The product of its digits is 432000, while the sum is 41.

Adding to 1345514534213 its reverse (3124354155431), we get a palindrome (4469868689644).

The spelling of 1345514534213 in words is "one trillion, three hundred forty-five billion, five hundred fourteen million, five hundred thirty-four thousand, two hundred thirteen".

Divisors: 1 79 17031829547 1345514534213