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13455340044415 = 52691068008883
BaseRepresentation
bin1100001111001101000011…
…0000111000000001111111
31202122022120210010102200221
43003303100300320001333
53230423014022410130
644341144202002211
72556054604203643
oct303632060700177
952568523112627
1013455340044415
114318417747595
12161389a1a6367
13767aaa4a3969
14347355c14c23
1518500e64a87a
hexc3cd0c3807f

13455340044415 has 4 divisors (see below), whose sum is σ = 16146408053304. Its totient is φ = 10764272035528.

The previous prime is 13455340044403. The next prime is 13455340044469. The reversal of 13455340044415 is 51444004355431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13455340044415 - 223 = 13455331655807 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1345534004437 + ... + 1345534004446.

It is an arithmetic number, because the mean of its divisors is an integer number (4036602013326).

Almost surely, 213455340044415 is an apocalyptic number.

13455340044415 is a deficient number, since it is larger than the sum of its proper divisors (2691068008889).

13455340044415 is an equidigital number, since it uses as much as digits as its factorization.

13455340044415 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2691068008888.

The product of its (nonzero) digits is 1152000, while the sum is 43.

Adding to 13455340044415 its reverse (51444004355431), we get a palindrome (64899344399846).

The spelling of 13455340044415 in words is "thirteen trillion, four hundred fifty-five billion, three hundred forty million, forty-four thousand, four hundred fifteen".

Divisors: 1 5 2691068008883 13455340044415