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13456045131 = 34485348377
BaseRepresentation
bin11001000100000101…
…01111010001001011
31021201202220220202220
430202002233101023
5210024221421011
610103121425123
7654311332164
oct144202572113
937652826686
1013456045131
11578564a961
12273649b1a3
131365a070a9
1491915c76b
1553b4d6506
hex3220af44b

13456045131 has 4 divisors (see below), whose sum is σ = 17941393512. Its totient is φ = 8970696752.

The previous prime is 13456045129. The next prime is 13456045133. The reversal of 13456045131 is 13154065431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13456045129) and next prime (13456045133).

It is a cyclic number.

It is not a de Polignac number, because 13456045131 - 21 = 13456045129 is a prime.

It is a super-2 number, since 2×134560451312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13456045092 and 13456045101.

It is not an unprimeable number, because it can be changed into a prime (13456045133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2242674186 + ... + 2242674191.

It is an arithmetic number, because the mean of its divisors is an integer number (4485348378).

Almost surely, 213456045131 is an apocalyptic number.

13456045131 is a deficient number, since it is larger than the sum of its proper divisors (4485348381).

13456045131 is an equidigital number, since it uses as much as digits as its factorization.

13456045131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4485348380.

The product of its (nonzero) digits is 21600, while the sum is 33.

The spelling of 13456045131 in words is "thirteen billion, four hundred fifty-six million, forty-five thousand, one hundred thirty-one".

Divisors: 1 3 4485348377 13456045131