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134613443461 = 719230491923
BaseRepresentation
bin111110101011110010…
…1100010001110000101
3110212110102221110022011
41331113211202032011
54201142020142321
6141501321134221
712503563250560
oct1752745421605
9425412843264
10134613443461
11520a8863522
122210992a371
13c90391ab33
1467300a54d7
15377cdaeae1
hex1f57962385

134613443461 has 4 divisors (see below), whose sum is σ = 153843935392. Its totient is φ = 115382951532.

The previous prime is 134613443449. The next prime is 134613443477. The reversal of 134613443461 is 164344316431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134613443461 - 213 = 134613435269 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134613443441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9615245955 + ... + 9615245968.

It is an arithmetic number, because the mean of its divisors is an integer number (38460983848).

Almost surely, 2134613443461 is an apocalyptic number.

It is an amenable number.

134613443461 is a deficient number, since it is larger than the sum of its proper divisors (19230491931).

134613443461 is an equidigital number, since it uses as much as digits as its factorization.

134613443461 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19230491930.

The product of its digits is 248832, while the sum is 40.

Adding to 134613443461 its reverse (164344316431), we get a palindrome (298957759892).

The spelling of 134613443461 in words is "one hundred thirty-four billion, six hundred thirteen million, four hundred forty-three thousand, four hundred sixty-one".

Divisors: 1 7 19230491923 134613443461