13484030631 has 4 divisors (see below), whose sum is σ = 17978707512. Its totient is φ = 8989353752.

The previous prime is 13484030587. The next prime is 13484030633. The reversal of 13484030631 is 13603048431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13484030631 - 2¹¹ = 13484028583 is a prime.

It is a super-2 number, since 2×13484030631² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13484030592 and 13484030601.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13484030633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2247338436 + ... + 2247338441.

It is an arithmetic number, because the mean of its divisors is an integer number (4494676878).

Almost surely, 2^13484030631 is an apocalyptic number.

13484030631 is a deficient number, since it is larger than the sum of its proper divisors (4494676881).

13484030631 is an equidigital number, since it uses as much as digits as its factorization.

13484030631 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4494676880.

The product of its (nonzero) digits is 20736, while the sum is 33.

The spelling of 13484030631 in words is "thirteen billion, four hundred eighty-four million, thirty thousand, six hundred thirty-one".