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13485343410321 = 34495114470107
BaseRepresentation
bin1100010000111100110100…
…0110101000100010010001
31202202012000202202100020020
43010033031012220202101
53231420440403112241
644403025314134053
72561166244461636
oct304171506504221
952665022670206
1013485343410321
11432a11387a462
121619672281329
1376a87c476b03
143489a089818d
15185bb86dbb66
hexc43cd1a8891

13485343410321 has 4 divisors (see below), whose sum is σ = 17980457880432. Its totient is φ = 8990228940212.

The previous prime is 13485343410317. The next prime is 13485343410347. The reversal of 13485343410321 is 12301434358431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13485343410321 - 22 = 13485343410317 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13485343410361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2247557235051 + ... + 2247557235056.

It is an arithmetic number, because the mean of its divisors is an integer number (4495114470108).

Almost surely, 213485343410321 is an apocalyptic number.

It is an amenable number.

13485343410321 is a deficient number, since it is larger than the sum of its proper divisors (4495114470111).

13485343410321 is an equidigital number, since it uses as much as digits as its factorization.

13485343410321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4495114470110.

The product of its (nonzero) digits is 414720, while the sum is 42.

Adding to 13485343410321 its reverse (12301434358431), we get a palindrome (25786777768752).

The spelling of 13485343410321 in words is "thirteen trillion, four hundred eighty-five billion, three hundred forty-three million, four hundred ten thousand, three hundred twenty-one".

Divisors: 1 3 4495114470107 13485343410321