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13485343410347 is a prime number
BaseRepresentation
bin1100010000111100110100…
…0110101000100010101011
31202202012000202202100021012
43010033031012220202223
53231420440403112342
644403025314134135
72561166244462004
oct304171506504253
952665022670235
1013485343410347
11432a11387a486
12161967228134b
1376a87c476b23
143489a08981ab
15185bb86dbb82
hexc43cd1a88ab

13485343410347 has 2 divisors, whose sum is σ = 13485343410348. Its totient is φ = 13485343410346.

The previous prime is 13485343410317. The next prime is 13485343410361. The reversal of 13485343410347 is 74301434358431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13485343410347 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13485343410295 and 13485343410304.

It is not a weakly prime, because it can be changed into another prime (13485343410317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6742671705173 + 6742671705174.

It is an arithmetic number, because the mean of its divisors is an integer number (6742671705174).

Almost surely, 213485343410347 is an apocalyptic number.

13485343410347 is a deficient number, since it is larger than the sum of its proper divisors (1).

13485343410347 is an equidigital number, since it uses as much as digits as its factorization.

13485343410347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5806080, while the sum is 50.

Adding to 13485343410347 its reverse (74301434358431), we get a palindrome (87786777768778).

The spelling of 13485343410347 in words is "thirteen trillion, four hundred eighty-five billion, three hundred forty-three million, four hundred ten thousand, three hundred forty-seven".