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13490335 = 517915073
BaseRepresentation
bin110011011101…
…100010011111
3221101101021001
4303131202133
511423142320
61201051131
7222444265
oct63354237
927341231
1013490335
117684541
124626aa7
132a44461
141b12435
1512b720a
hexcdd89f

13490335 has 8 divisors (see below), whose sum is σ = 16279920. Its totient is φ = 10731264.

The previous prime is 13490329. The next prime is 13490339. The reversal of 13490335 is 53309431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13490335 - 27 = 13490207 is a prime.

It is a super-3 number, since 3×134903353 (a number of 22 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13490339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6642 + ... + 8431.

It is an arithmetic number, because the mean of its divisors is an integer number (2034990).

Almost surely, 213490335 is an apocalyptic number.

13490335 is a deficient number, since it is larger than the sum of its proper divisors (2789585).

13490335 is a wasteful number, since it uses less digits than its factorization.

13490335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15257.

The product of its (nonzero) digits is 4860, while the sum is 28.

The square root of 13490335 is about 3672.9191387778. The cubic root of 13490335 is about 238.0533211511.

Adding to 13490335 its reverse (53309431), we get a palindrome (66799766).

The spelling of 13490335 in words is "thirteen million, four hundred ninety thousand, three hundred thirty-five".

Divisors: 1 5 179 895 15073 75365 2698067 13490335