Base | Representation |
---|---|
bin | 1100010001001111101010… |
… | …0100110101110110110111 |
3 | 1202202200002021000022000210 |
4 | 3010103322210311312313 |
5 | 3232011320211134343 |
6 | 44405223233440503 |
7 | 2561435501544042 |
oct | 304237244656667 |
9 | 52680067008023 |
10 | 13490401271223 |
11 | 4331279907198 |
12 | 161a644110133 |
13 | 76b1a72b3b06 |
14 | 348d204dbc59 |
15 | 185db2772333 |
hex | c44fa935db7 |
13490401271223 has 8 divisors (see below), whose sum is σ = 17987246477568. Its totient is φ = 8993578456184.
The previous prime is 13490401271189. The next prime is 13490401271287. The reversal of 13490401271223 is 32217210409431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13490401271223 - 226 = 13490334162359 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13490401271293) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4137615 + ... + 6640832.
It is an arithmetic number, because the mean of its divisors is an integer number (2248405809696).
Almost surely, 213490401271223 is an apocalyptic number.
13490401271223 is a deficient number, since it is larger than the sum of its proper divisors (4496845206345).
13490401271223 is a wasteful number, since it uses less digits than its factorization.
13490401271223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11195653.
The product of its (nonzero) digits is 72576, while the sum is 39.
The spelling of 13490401271223 in words is "thirteen trillion, four hundred ninety billion, four hundred one million, two hundred seventy-one thousand, two hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •