Base | Representation |
---|---|
bin | 101000001101001… |
… | …1010100100010011 |
3 | 10111000120110210221 |
4 | 1100122122210103 |
5 | 10230332224333 |
6 | 341511533511 |
7 | 45301114345 |
oct | 12032324423 |
9 | 3430513727 |
10 | 1349101843 |
11 | 632595201 |
12 | 31798a297 |
13 | 18666a61b |
14 | cb263295 |
15 | 7d68dd2d |
hex | 5069a913 |
1349101843 has 4 divisors (see below), whose sum is σ = 1382006808. Its totient is φ = 1316196880.
The previous prime is 1349101841. The next prime is 1349101849. The reversal of 1349101843 is 3481019431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3481019431 = 19 ⋅183211549.
It is a cyclic number.
It is not a de Polignac number, because 1349101843 - 21 = 1349101841 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1349101799 and 1349101808.
It is not an unprimeable number, because it can be changed into a prime (1349101841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16452421 + ... + 16452502.
It is an arithmetic number, because the mean of its divisors is an integer number (345501702).
Almost surely, 21349101843 is an apocalyptic number.
1349101843 is a deficient number, since it is larger than the sum of its proper divisors (32904965).
1349101843 is an equidigital number, since it uses as much as digits as its factorization.
1349101843 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32904964.
The product of its (nonzero) digits is 10368, while the sum is 34.
The square root of 1349101843 is about 36730.1217395205. The cubic root of 1349101843 is about 1104.9642960557.
The spelling of 1349101843 in words is "one billion, three hundred forty-nine million, one hundred one thousand, eight hundred forty-three".
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