134910320143 has 4 divisors (see below), whose sum is σ = 135085756960. Its totient is φ = 134734883328.

The previous prime is 134910320119. The next prime is 134910320239. The reversal of 134910320143 is 341023019431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134910320143 - 2⁹ = 134910319631 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134910329143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87717255 + ... + 87718792.

It is an arithmetic number, because the mean of its divisors is an integer number (33771439240).

Almost surely, 2^134910320143 is an apocalyptic number.

134910320143 is a deficient number, since it is larger than the sum of its proper divisors (175436817).

134910320143 is an equidigital number, since it uses as much as digits as its factorization.

134910320143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175436816.

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 134910320143 its reverse (341023019431), we get a palindrome (475933339574).

The spelling of 134910320143 in words is "one hundred thirty-four billion, nine hundred ten million, three hundred twenty thousand, one hundred forty-three".