Search a number
-
+
13491138535 = 57596533239
BaseRepresentation
bin11001001000010001…
…00110111111100111
31021211012221211212121
430210020212333213
5210112212413120
610110413530411
7655215533260
oct144410467747
937735854777
1013491138535
1157a343a076
1227461a3a07
131370073514
1491da95967
1553e6195aa
hex324226fe7

13491138535 has 16 divisors (see below), whose sum is σ = 18815731200. Its totient is φ = 9094267296.

The previous prime is 13491138487. The next prime is 13491138553. The reversal of 13491138535 is 53583119431.

It is a cyclic number.

It is not a de Polignac number, because 13491138535 - 221 = 13489041383 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13491138491 and 13491138500.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3264555 + ... + 3268684.

It is an arithmetic number, because the mean of its divisors is an integer number (1175983200).

Almost surely, 213491138535 is an apocalyptic number.

13491138535 is a deficient number, since it is larger than the sum of its proper divisors (5324592665).

13491138535 is an equidigital number, since it uses as much as digits as its factorization.

13491138535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6533310.

The product of its digits is 194400, while the sum is 43.

The spelling of 13491138535 in words is "thirteen billion, four hundred ninety-one million, one hundred thirty-eight thousand, five hundred thirty-five".

Divisors: 1 5 7 35 59 295 413 2065 6533239 32666195 45732673 228663365 385461101 1927305505 2698227707 13491138535