Base | Representation |
---|---|
bin | 11001001000010001… |
… | …00110111111100111 |
3 | 1021211012221211212121 |
4 | 30210020212333213 |
5 | 210112212413120 |
6 | 10110413530411 |
7 | 655215533260 |
oct | 144410467747 |
9 | 37735854777 |
10 | 13491138535 |
11 | 57a343a076 |
12 | 27461a3a07 |
13 | 1370073514 |
14 | 91da95967 |
15 | 53e6195aa |
hex | 324226fe7 |
13491138535 has 16 divisors (see below), whose sum is σ = 18815731200. Its totient is φ = 9094267296.
The previous prime is 13491138487. The next prime is 13491138553. The reversal of 13491138535 is 53583119431.
It is a cyclic number.
It is not a de Polignac number, because 13491138535 - 221 = 13489041383 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13491138491 and 13491138500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3264555 + ... + 3268684.
It is an arithmetic number, because the mean of its divisors is an integer number (1175983200).
Almost surely, 213491138535 is an apocalyptic number.
13491138535 is a deficient number, since it is larger than the sum of its proper divisors (5324592665).
13491138535 is an equidigital number, since it uses as much as digits as its factorization.
13491138535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6533310.
The product of its digits is 194400, while the sum is 43.
The spelling of 13491138535 in words is "thirteen billion, four hundred ninety-one million, one hundred thirty-eight thousand, five hundred thirty-five".
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