Base | Representation |
---|---|
bin | 11001001000010010… |
… | …10110111000010111 |
3 | 1021211020022210221012 |
4 | 30210021112320113 |
5 | 210112240202204 |
6 | 10110422042435 |
7 | 655220311154 |
oct | 144411267027 |
9 | 37736283835 |
10 | 13491334679 |
11 | 57a3563479 |
12 | 274627941b |
13 | 1370111894 |
14 | 91db0722b |
15 | 53e65776e |
hex | 324256e17 |
13491334679 has 4 divisors (see below), whose sum is σ = 13855965384. Its totient is φ = 13126703976.
The previous prime is 13491334643. The next prime is 13491334709. The reversal of 13491334679 is 97643319431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13491334679 is a prime.
It is a super-2 number, since 2×134913346792 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13491334609) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182315297 + ... + 182315370.
It is an arithmetic number, because the mean of its divisors is an integer number (3463991346).
Almost surely, 213491334679 is an apocalyptic number.
13491334679 is a deficient number, since it is larger than the sum of its proper divisors (364630705).
13491334679 is an equidigital number, since it uses as much as digits as its factorization.
13491334679 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364630704.
The product of its digits is 1469664, while the sum is 50.
The spelling of 13491334679 in words is "thirteen billion, four hundred ninety-one million, three hundred thirty-four thousand, six hundred seventy-nine".
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