13491458781 has 4 divisors (see below), whose sum is σ = 17988611712. Its totient is φ = 8994305852.

The previous prime is 13491458779. The next prime is 13491458789. The reversal of 13491458781 is 18785419431.

13491458781 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13491458781 - 2¹ = 13491458779 is a prime.

It is a super-2 number, since 2×13491458781² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13491458789) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2248576461 + ... + 2248576466.

It is an arithmetic number, because the mean of its divisors is an integer number (4497152928).

Almost surely, 2^13491458781 is an apocalyptic number.

It is an amenable number.

13491458781 is a deficient number, since it is larger than the sum of its proper divisors (4497152931).

13491458781 is an equidigital number, since it uses as much as digits as its factorization.

13491458781 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4497152930.

The product of its digits is 967680, while the sum is 51.

The spelling of 13491458781 in words is "thirteen billion, four hundred ninety-one million, four hundred fifty-eight thousand, seven hundred eighty-one".