Base | Representation |
---|---|
bin | 11001001000010111… |
… | …01001111001011011 |
3 | 1021211021110101222011 |
4 | 30210023221321123 |
5 | 210112413434414 |
6 | 10110443010351 |
7 | 655225366612 |
oct | 144413517133 |
9 | 37737411864 |
10 | 13491936859 |
11 | 57a3934945 |
12 | 27465099b7 |
13 | 13702929bb |
14 | 91dc22879 |
15 | 53e725dc4 |
hex | 3242e9e5b |
13491936859 has 4 divisors (see below), whose sum is σ = 13501419616. Its totient is φ = 13482454104.
The previous prime is 13491936853. The next prime is 13491936893. The reversal of 13491936859 is 95863919431.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13491936859 - 215 = 13491904091 is a prime.
It is a super-3 number, since 3×134919368593 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13491936853) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4739244 + ... + 4742089.
It is an arithmetic number, because the mean of its divisors is an integer number (3375354904).
Almost surely, 213491936859 is an apocalyptic number.
13491936859 is a deficient number, since it is larger than the sum of its proper divisors (9482757).
13491936859 is an equidigital number, since it uses as much as digits as its factorization.
13491936859 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9482756.
The product of its digits is 6298560, while the sum is 58.
The spelling of 13491936859 in words is "thirteen billion, four hundred ninety-one million, nine hundred thirty-six thousand, eight hundred fifty-nine".
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