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13497145 = 52699429
BaseRepresentation
bin110011011111…
…001100111001
3221101201121021
4303133030321
511423402040
61201142441
7222503164
oct63371471
927351537
1013497145
117689672
12462aa21
132a4759c
141b14adb
1512b924a
hexcdf339

13497145 has 4 divisors (see below), whose sum is σ = 16196580. Its totient is φ = 10797712.

The previous prime is 13497109. The next prime is 13497149. The reversal of 13497145 is 54179431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8573184 + 4923961 = 2928^2 + 2219^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13497145 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13497145.

It is not an unprimeable number, because it can be changed into a prime (13497149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1349710 + ... + 1349719.

It is an arithmetic number, because the mean of its divisors is an integer number (4049145).

Almost surely, 213497145 is an apocalyptic number.

It is an amenable number.

13497145 is a deficient number, since it is larger than the sum of its proper divisors (2699435).

13497145 is an equidigital number, since it uses as much as digits as its factorization.

13497145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2699434.

The product of its digits is 15120, while the sum is 34.

The square root of 13497145 is about 3673.8460773418. The cubic root of 13497145 is about 238.0933713155.

It can be divided in two parts, 134 and 97145, that added together give a palindrome (97279).

The spelling of 13497145 in words is "thirteen million, four hundred ninety-seven thousand, one hundred forty-five".

Divisors: 1 5 2699429 13497145