Base | Representation |
---|---|
bin | 11001001001000000… |
… | …11000101100101001 |
3 | 1021211122200111210200 |
4 | 30210200120230221 |
5 | 210120311341213 |
6 | 10111155302413 |
7 | 655322523060 |
oct | 144440305451 |
9 | 37748614720 |
10 | 13497371433 |
11 | 57a6a06a27 |
12 | 27482aaa09 |
13 | 1371446520 |
14 | 9208391d7 |
15 | 53ee4b273 |
hex | 324818b29 |
13497371433 has 48 divisors (see below), whose sum is σ = 24333394176. Its totient is φ = 7019187840.
The previous prime is 13497371399. The next prime is 13497371471. The reversal of 13497371433 is 33417379431.
13497371433 is a `hidden beast` number, since 13 + 497 + 3 + 7 + 143 + 3 = 666.
It is not a de Polignac number, because 13497371433 - 218 = 13497109289 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13497371233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 57910 + ... + 174207.
It is an arithmetic number, because the mean of its divisors is an integer number (506945712).
Almost surely, 213497371433 is an apocalyptic number.
13497371433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13497371433 is a deficient number, since it is larger than the sum of its proper divisors (10836022743).
13497371433 is a wasteful number, since it uses less digits than its factorization.
13497371433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 232214 (or 232211 counting only the distinct ones).
The product of its digits is 571536, while the sum is 45.
The spelling of 13497371433 in words is "thirteen billion, four hundred ninety-seven million, three hundred seventy-one thousand, four hundred thirty-three".
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