Base | Representation |
---|---|
bin | 11001001001000010… |
… | …10011101111110111 |
3 | 1021211200010210120211 |
4 | 30210201103233313 |
5 | 210120342111203 |
6 | 10111204410251 |
7 | 655324551166 |
oct | 144441235767 |
9 | 37750123524 |
10 | 13497613303 |
11 | 57a7061719 |
12 | 27483a6987 |
13 | 13714cc645 |
14 | 92089d3dd |
15 | 53ee97c6d |
hex | 324853bf7 |
13497613303 has 8 divisors (see below), whose sum is σ = 13528803456. Its totient is φ = 13466460600.
The previous prime is 13497613271. The next prime is 13497613351. The reversal of 13497613303 is 30331679431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13497613303 - 25 = 13497613271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13497643303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 788748 + ... + 805678.
It is an arithmetic number, because the mean of its divisors is an integer number (1691100432).
Almost surely, 213497613303 is an apocalyptic number.
13497613303 is a deficient number, since it is larger than the sum of its proper divisors (31190153).
13497613303 is an equidigital number, since it uses as much as digits as its factorization.
13497613303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18725.
The product of its (nonzero) digits is 122472, while the sum is 40.
The spelling of 13497613303 in words is "thirteen billion, four hundred ninety-seven million, six hundred thirteen thousand, three hundred three".
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