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1350000411200 = 265272374379137
BaseRepresentation
bin10011101001010010010…
…010111000001001000000
311210001120211221111220122
4103221102102320021000
5134104300101124300
62512103121555412
7166351161106100
oct23512222701100
94701524844818
101350000411200
11480594046181
121997804a5b68
139a3c5c7c37c
14494a9d85200
15251b384bc85
hex13a524b8240

1350000411200 has 1008 divisors, whose sum is σ = 4142338801920. Its totient is φ = 431136276480.

The previous prime is 1350000411143. The next prime is 1350000411271. The reversal of 1350000411200 is 21140000531.

It is a super-2 number, since 2×13500004112002 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 9854017532 + ... + 9854017668.

Almost surely, 21350000411200 is an apocalyptic number.

1350000411200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1350000411200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2071169400960).

1350000411200 is an abundant number, since it is smaller than the sum of its proper divisors (2792338390720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1350000411200 is a wasteful number, since it uses less digits than its factorization.

1350000411200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 332 (or 310 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 1350000411200 its reverse (21140000531), we get a palindrome (1371140411731).

The spelling of 1350000411200 in words is "one trillion, three hundred fifty billion, four hundred eleven thousand, two hundred".