13500031 has 4 divisors (see below), whose sum is σ = 13701592. Its totient is φ = 13298472.

The previous prime is 13500007. The next prime is 13500037. The reversal of 13500031 is 13000531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13000531 = 139 ⋅93529.

It is a cyclic number.

It is not a de Polignac number, because 13500031 - 2⁵ = 13499999 is a prime.

It is a super-2 number, since 2×13500031² = 364501674001922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13499984 and 13500020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13500037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100680 + ... + 100813.

It is an arithmetic number, because the mean of its divisors is an integer number (3425398).

Almost surely, 2^13500031 is an apocalyptic number.

13500031 is a deficient number, since it is larger than the sum of its proper divisors (201561).

13500031 is an equidigital number, since it uses as much as digits as its factorization.

13500031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201560.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 13500031 is about 3674.2388327380. The cubic root of 13500031 is about 238.1103400522.

Adding to 13500031 its reverse (13000531), we get a palindrome (26500562).

Subtracting from 13500031 its reverse (13000531), we obtain a triangular number (499500 = T₉₉₉).

The spelling of 13500031 in words is "thirteen million, five hundred thousand, thirty-one".