1350005244331 has 4 divisors (see below), whose sum is σ = 1350589917600. Its totient is φ = 1349420571064.

The previous prime is 1350005244319. The next prime is 1350005244337. The reversal of 1350005244331 is 1334425000531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1350005244331 is a prime.

It is a super-2 number, since 2×1350005244331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1350005244293 and 1350005244302.

It is not an unprimeable number, because it can be changed into a prime (1350005244337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292333171 + ... + 292337788.

It is an arithmetic number, because the mean of its divisors is an integer number (337647479400).

Almost surely, 2^{1350005244331} is an apocalyptic number.

1350005244331 is a deficient number, since it is larger than the sum of its proper divisors (584673269).

1350005244331 is an equidigital number, since it uses as much as digits as its factorization.

1350005244331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 584673268.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 1350005244331 in words is "one trillion, three hundred fifty billion, five million, two hundred forty-four thousand, three hundred thirty-one".