Base | Representation |
---|---|
bin | 10011101001010010100… |
… | …101010100000110110001 |
3 | 11210001121012001001201201 |
4 | 103221102211110012301 |
5 | 134104302320304322 |
6 | 2512103413331201 |
7 | 166351250145631 |
oct | 23512245240661 |
9 | 4701535031651 |
10 | 1350005244337 |
11 | 480596847402 |
12 | 199782036b01 |
13 | 9a3c6c82209 |
14 | 494aa8826c1 |
15 | 251b3ea3d27 |
hex | 13a529541b1 |
1350005244337 has 2 divisors, whose sum is σ = 1350005244338. Its totient is φ = 1350005244336.
The previous prime is 1350005244319. The next prime is 1350005244359. The reversal of 1350005244337 is 7334425000531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1221962219776 + 128043024561 = 1105424^2 + 357831^2 .
It is a cyclic number.
It is not a de Polignac number, because 1350005244337 - 235 = 1315645505969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1350005244296 and 1350005244305.
It is not a weakly prime, because it can be changed into another prime (1350005244377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675002622168 + 675002622169.
It is an arithmetic number, because the mean of its divisors is an integer number (675002622169).
Almost surely, 21350005244337 is an apocalyptic number.
It is an amenable number.
1350005244337 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350005244337 is an equidigital number, since it uses as much as digits as its factorization.
1350005244337 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 37.
The spelling of 1350005244337 in words is "one trillion, three hundred fifty billion, five million, two hundred forty-four thousand, three hundred thirty-seven".
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