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13500110054545 = 52700022010909
BaseRepresentation
bin1100010001110011110101…
…0000111010010010010001
31202210121010212210120222021
43010130331100322102101
53232141211133221140
644413510454411441
72562231212050552
oct304347520722221
952717125716867
1013500110054545
1143354011a6864
1216204b3660b81
1376c09385a30a
143495a1ad6329
1518627eca8b4a
hexc473d43a491

13500110054545 has 4 divisors (see below), whose sum is σ = 16200132065460. Its totient is φ = 10800088043632.

The previous prime is 13500110054531. The next prime is 13500110054551. The reversal of 13500110054545 is 54545001100531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8982440573184 + 4517669481361 = 2997072^2 + 2125481^2 .

It is a cyclic number.

It is not a de Polignac number, because 13500110054545 - 25 = 13500110054513 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13500110054545.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1350011005450 + ... + 1350011005459.

It is an arithmetic number, because the mean of its divisors is an integer number (4050033016365).

Almost surely, 213500110054545 is an apocalyptic number.

It is an amenable number.

13500110054545 is a deficient number, since it is larger than the sum of its proper divisors (2700022010915).

13500110054545 is an equidigital number, since it uses as much as digits as its factorization.

13500110054545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2700022010914.

The product of its (nonzero) digits is 30000, while the sum is 34.

The spelling of 13500110054545 in words is "thirteen trillion, five hundred billion, one hundred ten million, fifty-four thousand, five hundred forty-five".

Divisors: 1 5 2700022010909 13500110054545