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135003035131 = 3971447235009
BaseRepresentation
bin111110110111011001…
…1101101010111111011
3110220110121000202121021
41331232303231113323
54202441234111011
6142004115323311
712516333602416
oct1755663552773
9426417022537
10135003035131
115228876a508
12221b82b0537
13c966556a53
146769b1ab7d
1537a21b9471
hex1f6eced5fb

135003035131 has 8 divisors (see below), whose sum is σ = 135437203040. Its totient is φ = 134569340928.

The previous prime is 135003035033. The next prime is 135003035149. The reversal of 135003035131 is 131530300531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135003035131 - 29 = 135003034619 is a prime.

It is a super-2 number, since 2×1350030351312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135003035096 and 135003035105.

It is not an unprimeable number, because it can be changed into a prime (135003035831) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 456955 + ... + 691963.

It is an arithmetic number, because the mean of its divisors is an integer number (16929650380).

Almost surely, 2135003035131 is an apocalyptic number.

135003035131 is a deficient number, since it is larger than the sum of its proper divisors (434167909).

135003035131 is a wasteful number, since it uses less digits than its factorization.

135003035131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 236853.

The product of its (nonzero) digits is 2025, while the sum is 25.

Adding to 135003035131 its reverse (131530300531), we get a palindrome (266533335662).

The spelling of 135003035131 in words is "one hundred thirty-five billion, three million, thirty-five thousand, one hundred thirty-one".

Divisors: 1 397 1447 235009 574459 93298573 340058023 135003035131