13500345145011 has 4 divisors (see below), whose sum is σ = 18000460193352. Its totient is φ = 9000230096672.

The previous prime is 13500345145009. The next prime is 13500345145051. The reversal of 13500345145011 is 11054154300531.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13500345145011 - 2¹ = 13500345145009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13500345145051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2250057524166 + ... + 2250057524171.

It is an arithmetic number, because the mean of its divisors is an integer number (4500115048338).

Almost surely, 2^{13500345145011} is an apocalyptic number.

13500345145011 is a deficient number, since it is larger than the sum of its proper divisors (4500115048341).

13500345145011 is an equidigital number, since it uses as much as digits as its factorization.

13500345145011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4500115048340.

The product of its (nonzero) digits is 18000, while the sum is 33.

Adding to 13500345145011 its reverse (11054154300531), we get a palindrome (24554499445542).

The spelling of 13500345145011 in words is "thirteen trillion, five hundred billion, three hundred forty-five million, one hundred forty-five thousand, eleven".