Base | Representation |
---|---|
bin | 1100010001110101011001… |
… | …1111100101101000110111 |
3 | 1202210122020101021100012212 |
4 | 3010131112133211220313 |
5 | 3232143043013120120 |
6 | 44414020455004035 |
7 | 2562244541623304 |
oct | 304352637455067 |
9 | 52718211240185 |
10 | 13500533332535 |
11 | 43355a9120887 |
12 | 16205b136961b |
13 | 76c13045c072 |
14 | 349601dda0ab |
15 | 1862a70196c5 |
hex | c47567e5a37 |
13500533332535 has 8 divisors (see below), whose sum is σ = 16213326490656. Its totient is φ = 10791969004960.
The previous prime is 13500533332529. The next prime is 13500533332541. The reversal of 13500533332535 is 53523333500531.
It is an interprime number because it is at equal distance from previous prime (13500533332529) and next prime (13500533332541).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13500533332535 - 234 = 13483353463351 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13500533332492 and 13500533332501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1057200611 + ... + 1057213380.
It is an arithmetic number, because the mean of its divisors is an integer number (2026665811332).
Almost surely, 213500533332535 is an apocalyptic number.
13500533332535 is a deficient number, since it is larger than the sum of its proper divisors (2712793158121).
13500533332535 is a wasteful number, since it uses less digits than its factorization.
13500533332535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2114415273.
The product of its (nonzero) digits is 911250, while the sum is 41.
The spelling of 13500533332535 in words is "thirteen trillion, five hundred billion, five hundred thirty-three million, three hundred thirty-two thousand, five hundred thirty-five".
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