Base | Representation |
---|---|
bin | 1100010001110111001010… |
… | …0100001110101000111011 |
3 | 1202210200110012111112100101 |
4 | 3010131302210032220323 |
5 | 3232200024100423344 |
6 | 44414135321420231 |
7 | 2562262321105534 |
oct | 304356244165073 |
9 | 52720405445311 |
10 | 13501004311099 |
11 | 433581aa65a68 |
12 | 162070303a677 |
13 | 76c1a6bc26c6 |
14 | 34964879968b |
15 | 1862d354d9d4 |
hex | c477290ea3b |
13501004311099 has 4 divisors (see below), whose sum is σ = 13502719167736. Its totient is φ = 13499289454464.
The previous prime is 13501004311079. The next prime is 13501004311141. The reversal of 13501004311099 is 99011340010531.
13501004311099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13501004311099 - 219 = 13501003786811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13501004311019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857416509 + ... + 857432254.
It is an arithmetic number, because the mean of its divisors is an integer number (3375679791934).
Almost surely, 213501004311099 is an apocalyptic number.
13501004311099 is a deficient number, since it is larger than the sum of its proper divisors (1714856637).
13501004311099 is an equidigital number, since it uses as much as digits as its factorization.
13501004311099 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1714856636.
The product of its (nonzero) digits is 14580, while the sum is 37.
The spelling of 13501004311099 in words is "thirteen trillion, five hundred one billion, four million, three hundred eleven thousand, ninety-nine".
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