13501004311141 has 2 divisors, whose sum is σ = 13501004311142. Its totient is φ = 13501004311140.

The previous prime is 13501004311079. The next prime is 13501004311183. The reversal of 13501004311141 is 14111340010531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9240718421025 + 4260285890116 = 3039855^2 + 2064046^2 .

It is a cyclic number.

It is not a de Polignac number, because 13501004311141 - 2¹³ = 13501004302949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13501004381141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750502155570 + 6750502155571.

It is an arithmetic number, because the mean of its divisors is an integer number (6750502155571).

Almost surely, 2^{13501004311141} is an apocalyptic number.

It is an amenable number.

13501004311141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13501004311141 is an equidigital number, since it uses as much as digits as its factorization.

13501004311141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 13501004311141 its reverse (14111340010531), we get a palindrome (27612344321672).

The spelling of 13501004311141 in words is "thirteen trillion, five hundred one billion, four million, three hundred eleven thousand, one hundred forty-one".