13501036571341 has 4 divisors (see below), whose sum is σ = 14728403532384. Its totient is φ = 12273669610300.

The previous prime is 13501036571329. The next prime is 13501036571377. The reversal of 13501036571341 is 14317563010531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13501036571341 - 2¹³ = 13501036563149 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13501036571294 and 13501036571303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13501036541341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 613683480505 + ... + 613683480526.

It is an arithmetic number, because the mean of its divisors is an integer number (3682100883096).

Almost surely, 2^{13501036571341} is an apocalyptic number.

13501036571341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13501036571341 is a deficient number, since it is larger than the sum of its proper divisors (1227366961043).

13501036571341 is a wasteful number, since it uses less digits than its factorization.

13501036571341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1227366961042.

The product of its (nonzero) digits is 113400, while the sum is 40.

Adding to 13501036571341 its reverse (14317563010531), we get a palindrome (27818599581872).

The spelling of 13501036571341 in words is "thirteen trillion, five hundred one billion, thirty-six million, five hundred seventy-one thousand, three hundred forty-one".