Base | Representation |
---|---|
bin | 11001001001011101… |
… | …01111110111001111 |
3 | 1021211220202210021111 |
4 | 30210232233313033 |
5 | 210122242330320 |
6 | 10111412112451 |
7 | 655366523341 |
oct | 144456576717 |
9 | 37756683244 |
10 | 13501136335 |
11 | 57a9048615 |
12 | 2749605727 |
13 | 137216408b |
14 | 921139291 |
15 | 540441a5a |
hex | 324bafdcf |
13501136335 has 4 divisors (see below), whose sum is σ = 16201363608. Its totient is φ = 10800909064.
The previous prime is 13501136333. The next prime is 13501136357. The reversal of 13501136335 is 53363110531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53363110531 = 3313 ⋅16107187.
It is a cyclic number.
It is not a de Polignac number, because 13501136335 - 21 = 13501136333 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13501136297 and 13501136306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13501136333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1350113629 + ... + 1350113638.
It is an arithmetic number, because the mean of its divisors is an integer number (4050340902).
Almost surely, 213501136335 is an apocalyptic number.
13501136335 is a deficient number, since it is larger than the sum of its proper divisors (2700227273).
13501136335 is an equidigital number, since it uses as much as digits as its factorization.
13501136335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2700227272.
The product of its (nonzero) digits is 12150, while the sum is 31.
Adding to 13501136335 its reverse (53363110531), we get a palindrome (66864246866).
The spelling of 13501136335 in words is "thirteen billion, five hundred one million, one hundred thirty-six thousand, three hundred thirty-five".
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