135011441131 has 4 divisors (see below), whose sum is σ = 154298789872. Its totient is φ = 115724092392.

The previous prime is 135011441069. The next prime is 135011441167. The reversal of 135011441131 is 131144110531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135011441131 - 2⁷ = 135011441003 is a prime.

It is a super-2 number, since 2×135011441131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135011441096 and 135011441105.

It is not an unprimeable number, because it can be changed into a prime (135011441431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9643674360 + ... + 9643674373.

It is an arithmetic number, because the mean of its divisors is an integer number (38574697468).

Almost surely, 2^135011441131 is an apocalyptic number.

135011441131 is a deficient number, since it is larger than the sum of its proper divisors (19287348741).

135011441131 is an equidigital number, since it uses as much as digits as its factorization.

135011441131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19287348740.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 135011441131 its reverse (131144110531), we get a palindrome (266155551662).

The spelling of 135011441131 in words is "one hundred thirty-five billion, eleven million, four hundred forty-one thousand, one hundred thirty-one".