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1350125103 = 3450041701
BaseRepresentation
bin101000001111001…
…0100011000101111
310111002111110110110
41100132110120233
510231113000403
6341545511103
745312605535
oct12036243057
93432443413
101350125103
11633123a78
123181a2493
131869382c2
14cb44c155
157d7e2103
hex5079462f

1350125103 has 4 divisors (see below), whose sum is σ = 1800166808. Its totient is φ = 900083400.

The previous prime is 1350125099. The next prime is 1350125129. The reversal of 1350125103 is 3015210531.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1350125103 - 22 = 1350125099 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1350125103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350105103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225020848 + ... + 225020853.

It is an arithmetic number, because the mean of its divisors is an integer number (450041702).

Almost surely, 21350125103 is an apocalyptic number.

1350125103 is a deficient number, since it is larger than the sum of its proper divisors (450041705).

1350125103 is an equidigital number, since it uses as much as digits as its factorization.

1350125103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450041704.

The product of its (nonzero) digits is 450, while the sum is 21.

The square root of 1350125103 is about 36744.0485385048. The cubic root of 1350125103 is about 1105.2435880482.

Adding to 1350125103 its reverse (3015210531), we get a palindrome (4365335634).

The spelling of 1350125103 in words is "one billion, three hundred fifty million, one hundred twenty-five thousand, one hundred three".

Divisors: 1 3 450041701 1350125103