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135016330535 = 546358322389
BaseRepresentation
bin111110110111110011…
…0011011010100100111
3110220111112001020110122
41331233212123110213
54203003140034120
6142005312312155
712516554605502
oct1755746332447
9426445036418
10135016330535
1152295220549
122220084265b
13c969230558
14676b7bc139
1537a3443a25
hex1f6f99b527

135016330535 has 8 divisors (see below), whose sum is σ = 162369533760. Its totient is φ = 107779773024.

The previous prime is 135016330529. The next prime is 135016330549. The reversal of 135016330535 is 535033610531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135016330535 is a prime.

It is a super-2 number, since 2×1350163305352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 135016330495 and 135016330504.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29158880 + ... + 29163509.

It is an arithmetic number, because the mean of its divisors is an integer number (20296191720).

Almost surely, 2135016330535 is an apocalyptic number.

135016330535 is a deficient number, since it is larger than the sum of its proper divisors (27353203225).

135016330535 is an equidigital number, since it uses as much as digits as its factorization.

135016330535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58322857.

The product of its (nonzero) digits is 60750, while the sum is 35.

The spelling of 135016330535 in words is "one hundred thirty-five billion, sixteen million, three hundred thirty thousand, five hundred thirty-five".

Divisors: 1 5 463 2315 58322389 291611945 27003266107 135016330535