Base | Representation |
---|---|
bin | 10011101001011111101… |
… | …000101001000101110011 |
3 | 11210002011110002012121010 |
4 | 103221133220221011303 |
5 | 134110224400024111 |
6 | 2512141235002003 |
7 | 166356546336324 |
oct | 23513750510563 |
9 | 4702143065533 |
10 | 1350224220531 |
11 | 48069941046a |
12 | 199823439303 |
13 | 9a430451924 |
14 | 494cb9a444b |
15 | 251c830aaa6 |
hex | 13a5fa29173 |
1350224220531 has 4 divisors (see below), whose sum is σ = 1800298960712. Its totient is φ = 900149480352.
The previous prime is 1350224220523. The next prime is 1350224220637.
1350224220531 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1350224220531 - 23 = 1350224220523 is a prime.
It is a super-2 number, since 2×13502242205312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1350224221531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225037370086 + ... + 225037370091.
It is an arithmetic number, because the mean of its divisors is an integer number (450074740178).
Almost surely, 21350224220531 is an apocalyptic number.
1350224220531 is a deficient number, since it is larger than the sum of its proper divisors (450074740181).
1350224220531 is an equidigital number, since it uses as much as digits as its factorization.
1350224220531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 450074740180.
The product of its (nonzero) digits is 14400, while the sum is 30.
The spelling of 1350224220531 in words is "one trillion, three hundred fifty billion, two hundred twenty-four million, two hundred twenty thousand, five hundred thirty-one".
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