13502247113 has 4 divisors (see below), whose sum is σ = 13502499780. Its totient is φ = 13501994448.

The previous prime is 13502247107. The next prime is 13502247131. The reversal of 13502247113 is 31174220531.

13502247113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5059761424 + 8442485689 = 71132^2 + 91883^2 .

It is a cyclic number.

It is not a de Polignac number, because 13502247113 - 2¹² = 13502243017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13502247103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11198 + ... + 164711.

It is an arithmetic number, because the mean of its divisors is an integer number (3375624945).

Almost surely, 2^13502247113 is an apocalyptic number.

It is an amenable number.

13502247113 is a deficient number, since it is larger than the sum of its proper divisors (252667).

13502247113 is an equidigital number, since it uses as much as digits as its factorization.

13502247113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 252666.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 13502247113 its reverse (31174220531), we get a palindrome (44676467644).

The spelling of 13502247113 in words is "thirteen billion, five hundred two million, two hundred forty-seven thousand, one hundred thirteen".