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13502247131 is a prime number
BaseRepresentation
bin11001001001100101…
…11111000011011011
31021211222212020000002
430210302333003123
5210123033402011
610111452003215
7655412130662
oct144462770333
937758766002
1013502247131
1157a973712a
122749a6050b
131372462859
14921347dd9
155405b0c3b
hex324cbf0db

13502247131 has 2 divisors, whose sum is σ = 13502247132. Its totient is φ = 13502247130.

The previous prime is 13502247107. The next prime is 13502247179. The reversal of 13502247131 is 13174220531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13502247131 - 230 = 12428505307 is a prime.

It is a super-2 number, since 2×135022471312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13502247094 and 13502247103.

It is not a weakly prime, because it can be changed into another prime (13502247181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751123565 + 6751123566.

It is an arithmetic number, because the mean of its divisors is an integer number (6751123566).

Almost surely, 213502247131 is an apocalyptic number.

13502247131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13502247131 is an equidigital number, since it uses as much as digits as its factorization.

13502247131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 13502247131 its reverse (13174220531), we get a palindrome (26676467662).

The spelling of 13502247131 in words is "thirteen billion, five hundred two million, two hundred forty-seven thousand, one hundred thirty-one".