Base | Representation |
---|---|
bin | 1100010001111100100001… |
… | …0110010101100110000001 |
3 | 1202210211011111121102021202 |
4 | 3010133020112111212001 |
5 | 3232211001014311040 |
6 | 44414534212430545 |
7 | 2562343065102242 |
oct | 304371026254601 |
9 | 52724144542252 |
10 | 13502443510145 |
11 | 4336399398567 |
12 | 1620a45018455 |
13 | 76c376117285 |
14 | 349743992cc9 |
15 | 186369a88015 |
hex | c47c8595981 |
13502443510145 has 16 divisors (see below), whose sum is σ = 16243234076160. Its totient is φ = 10775116746624.
The previous prime is 13502443510139. The next prime is 13502443510219. The reversal of 13502443510145 is 54101534420531.
It is a cyclic number.
It is not a de Polignac number, because 13502443510145 - 214 = 13502443493761 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13502443510099 and 13502443510108.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1756166 + ... + 5485344.
It is an arithmetic number, because the mean of its divisors is an integer number (1015202129760).
Almost surely, 213502443510145 is an apocalyptic number.
It is an amenable number.
13502443510145 is a deficient number, since it is larger than the sum of its proper divisors (2740790566015).
13502443510145 is a wasteful number, since it uses less digits than its factorization.
13502443510145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3730984.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 13502443510145 its reverse (54101534420531), we get a palindrome (67603977930676).
The spelling of 13502443510145 in words is "thirteen trillion, five hundred two billion, four hundred forty-three million, five hundred ten thousand, one hundred forty-five".
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