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135027305345 = 527005461069
BaseRepresentation
bin111110111000001000…
…0010010101110000001
3110220112021200211002002
41331300100102232001
54203013442232340
6142010343433345
712520050105152
oct1756020225601
9426467624062
10135027305345
11522a0437039
1222204455855
13c96b5a3a1a
14676d037929
1537a43b0715
hex1f70412b81

135027305345 has 4 divisors (see below), whose sum is σ = 162032766420. Its totient is φ = 108021844272.

The previous prime is 135027305321. The next prime is 135027305393. The reversal of 135027305345 is 543503720531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 543503720531 = 553198265001.

It can be written as a sum of positive squares in 2 ways, for example, as 41498986369 + 93528318976 = 203713^2 + 305824^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135027305345 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 135027305299 and 135027305308.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13502730530 + ... + 13502730539.

It is an arithmetic number, because the mean of its divisors is an integer number (40508191605).

Almost surely, 2135027305345 is an apocalyptic number.

It is an amenable number.

135027305345 is a deficient number, since it is larger than the sum of its proper divisors (27005461075).

135027305345 is an equidigital number, since it uses as much as digits as its factorization.

135027305345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27005461074.

The product of its (nonzero) digits is 189000, while the sum is 38.

The spelling of 135027305345 in words is "one hundred thirty-five billion, twenty-seven million, three hundred five thousand, three hundred forty-five".

Divisors: 1 5 27005461069 135027305345