13503042542233 has 4 divisors (see below), whose sum is σ = 13509291060148. Its totient is φ = 13496794024320.

The previous prime is 13503042542219. The next prime is 13503042542317. The reversal of 13503042542233 is 33224524030531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3337479573129 + 10165562969104 = 1826877^2 + 3188348^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13503042542233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13503042542192 and 13503042542201.

It is not an unprimeable number, because it can be changed into a prime (13503072542233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3124255716 + ... + 3124260037.

It is an arithmetic number, because the mean of its divisors is an integer number (3377322765037).

Almost surely, 2^{13503042542233} is an apocalyptic number.

It is an amenable number.

13503042542233 is a deficient number, since it is larger than the sum of its proper divisors (6248517915).

13503042542233 is an equidigital number, since it uses as much as digits as its factorization.

13503042542233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6248517914.

The product of its (nonzero) digits is 259200, while the sum is 37.

Adding to 13503042542233 its reverse (33224524030531), we get a palindrome (46727566572764).

The spelling of 13503042542233 in words is "thirteen trillion, five hundred three billion, forty-two million, five hundred forty-two thousand, two hundred thirty-three".