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13503042542317 is a prime number
BaseRepresentation
bin1100010001111110110000…
…0011011101101011101101
31202210212201020210101221111
43010133230003131223231
53232213212342323232
644415113452032021
72562363660560566
oct304375403355355
952725636711844
1013503042542317
114336676545279
121620b91762611
1376c440264493
1434979d36716d
151863a2464047
hexc47ec0ddaed

13503042542317 has 2 divisors, whose sum is σ = 13503042542318. Its totient is φ = 13503042542316.

The previous prime is 13503042542219. The next prime is 13503042542321. The reversal of 13503042542317 is 71324524030531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12663484499241 + 839558043076 = 3558579^2 + 916274^2 .

It is a cyclic number.

It is not a de Polignac number, because 13503042542317 - 223 = 13503034153709 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13503042542317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13503042542617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751521271158 + 6751521271159.

It is an arithmetic number, because the mean of its divisors is an integer number (6751521271159).

Almost surely, 213503042542317 is an apocalyptic number.

It is an amenable number.

13503042542317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13503042542317 is an equidigital number, since it uses as much as digits as its factorization.

13503042542317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 40.

Adding to 13503042542317 its reverse (71324524030531), we get a palindrome (84827566572848).

The spelling of 13503042542317 in words is "thirteen trillion, five hundred three billion, forty-two million, five hundred forty-two thousand, three hundred seventeen".