Base | Representation |
---|---|
bin | 111110111000001111… |
… | …0111101111000001111 |
3 | 110220112112221020220002 |
4 | 1331300132331320033 |
5 | 4203020433332033 |
6 | 142011002114515 |
7 | 12520124566256 |
oct | 1756036757017 |
9 | 426475836802 |
10 | 135031152143 |
11 | 522a2624208 |
12 | 222057aba3b |
13 | c96c31c934 |
14 | 676d75979d |
15 | 37a48c03e8 |
hex | 1f707bde0f |
135031152143 has 4 divisors (see below), whose sum is σ = 135811679208. Its totient is φ = 134250625080.
The previous prime is 135031152131. The next prime is 135031152161. The reversal of 135031152143 is 341251130531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135031152143 - 28 = 135031151887 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135031152343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 390263273 + ... + 390263618.
It is an arithmetic number, because the mean of its divisors is an integer number (33952919802).
Almost surely, 2135031152143 is an apocalyptic number.
135031152143 is a deficient number, since it is larger than the sum of its proper divisors (780527065).
135031152143 is an equidigital number, since it uses as much as digits as its factorization.
135031152143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 780527064.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 135031152143 its reverse (341251130531), we get a palindrome (476282282674).
The spelling of 135031152143 in words is "one hundred thirty-five billion, thirty-one million, one hundred fifty-two thousand, one hundred forty-three".
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