13504013 has 4 divisors (see below), whose sum is σ = 14091168. Its totient is φ = 12916860.

The previous prime is 13503991. The next prime is 13504033. The reversal of 13504013 is 31040531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31040531 = 1543 ⋅20117.

It is a cyclic number.

It is not a de Polignac number, because 13504013 - 2⁶ = 13503949 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13503982 and 13504000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13504033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 293543 + ... + 293588.

It is an arithmetic number, because the mean of its divisors is an integer number (3522792).

Almost surely, 2^13504013 is an apocalyptic number.

It is an amenable number.

13504013 is a deficient number, since it is larger than the sum of its proper divisors (587155).

13504013 is an equidigital number, since it uses as much as digits as its factorization.

13504013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 587154.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 13504013 is about 3674.7806737273. The cubic root of 13504013 is about 238.1337489409.

Adding to 13504013 its reverse (31040531), we get a palindrome (44544544).

The spelling of 13504013 in words is "thirteen million, five hundred four thousand, thirteen".