Base | Representation |
---|---|
bin | 10011101001101011000… |
… | …000100000001110011011 |
3 | 11210002122202010002012012 |
4 | 103221223000200032123 |
5 | 134111122221300201 |
6 | 2512212212340135 |
7 | 166364354214611 |
oct | 23515300401633 |
9 | 4702582102165 |
10 | 1350415025051 |
11 | 480787092754 |
12 | 19987731464b |
13 | 9a460b39601 |
14 | 495090716b1 |
15 | 251d9e4a5bb |
hex | 13a6b02039b |
1350415025051 has 4 divisors (see below), whose sum is σ = 1350736480104. Its totient is φ = 1350093570000.
The previous prime is 1350415025041. The next prime is 1350415025053. The reversal of 1350415025051 is 1505205140531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1350415025051 - 226 = 1350347916187 is a prime.
It is a super-3 number, since 3×13504150250513 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1350415024999 and 1350415025017.
It is not an unprimeable number, because it can be changed into a prime (1350415025053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160721225 + ... + 160729626.
It is an arithmetic number, because the mean of its divisors is an integer number (337684120026).
Almost surely, 21350415025051 is an apocalyptic number.
1350415025051 is a deficient number, since it is larger than the sum of its proper divisors (321455053).
1350415025051 is an equidigital number, since it uses as much as digits as its factorization.
1350415025051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 321455052.
The product of its (nonzero) digits is 15000, while the sum is 32.
The spelling of 1350415025051 in words is "one trillion, three hundred fifty billion, four hundred fifteen million, twenty-five thousand, fifty-one".
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