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13504334334501 = 34501444778167
BaseRepresentation
bin1100010010000011100100…
…0011010000101000100101
31202211000001021112020200110
43010200321003100220211
53232223334042201001
644415445555403233
72562440664614553
oct304407103205045
952730037466613
1013504334334501
11433717974691a
1216212922b3519
1376c5b7a8755a
14349882b4cbd3
1518642aa823d6
hexc48390d0a25

13504334334501 has 4 divisors (see below), whose sum is σ = 18005779112672. Its totient is φ = 9002889556332.

The previous prime is 13504334334473. The next prime is 13504334334509. The reversal of 13504334334501 is 10543343340531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13504334334501 - 27 = 13504334334373 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13504334334501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13504334334509) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2250722389081 + ... + 2250722389086.

It is an arithmetic number, because the mean of its divisors is an integer number (4501444778168).

Almost surely, 213504334334501 is an apocalyptic number.

It is an amenable number.

13504334334501 is a deficient number, since it is larger than the sum of its proper divisors (4501444778171).

13504334334501 is an equidigital number, since it uses as much as digits as its factorization.

13504334334501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4501444778170.

The product of its (nonzero) digits is 388800, while the sum is 39.

The spelling of 13504334334501 in words is "thirteen trillion, five hundred four billion, three hundred thirty-four million, three hundred thirty-four thousand, five hundred one".

Divisors: 1 3 4501444778167 13504334334501