Base | Representation |
---|---|
bin | 10011101001101100101… |
… | …001000101111011010101 |
3 | 11210002201122201000210112 |
4 | 103221230221011323111 |
5 | 134111201231124303 |
6 | 2512215032132405 |
7 | 166365136235666 |
oct | 23515451057325 |
9 | 4702648630715 |
10 | 1350442442453 |
11 | 4807a0609865 |
12 | 199884537105 |
13 | 9a466718c20 |
14 | 4950c96b36d |
15 | 251dc5640d8 |
hex | 13a6ca45ed5 |
1350442442453 has 8 divisors (see below), whose sum is σ = 1464083187000. Its totient is φ = 1238196063168.
The previous prime is 1350442442449. The next prime is 1350442442497. The reversal of 1350442442453 is 3542442440531.
It can be written as a sum of positive squares in 4 ways, for example, as 143252409169 + 1207190033284 = 378487^2 + 1098722^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1350442442453 - 22 = 1350442442449 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1350442442453.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1350442442413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 348589298 + ... + 348593171.
It is an arithmetic number, because the mean of its divisors is an integer number (183010398375).
Almost surely, 21350442442453 is an apocalyptic number.
1350442442453 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1350442442453 is a deficient number, since it is larger than the sum of its proper divisors (113640744547).
1350442442453 is a wasteful number, since it uses less digits than its factorization.
1350442442453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 697182631.
The product of its (nonzero) digits is 921600, while the sum is 41.
Adding to 1350442442453 its reverse (3542442440531), we get a palindrome (4892884882984).
The spelling of 1350442442453 in words is "one trillion, three hundred fifty billion, four hundred forty-two million, four hundred forty-two thousand, four hundred fifty-three".
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