1350483933 has 4 divisors (see below), whose sum is σ = 1800645248. Its totient is φ = 900322620.

The previous prime is 1350483931. The next prime is 1350483991. The reversal of 1350483933 is 3393840531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1350483933 - 2¹ = 1350483931 is a prime.

It is a super-2 number, since 2×1350483933² = 3647613706582296978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1350483891 and 1350483900.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350483931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225080653 + ... + 225080658.

It is an arithmetic number, because the mean of its divisors is an integer number (450161312).

Almost surely, 2^1350483933 is an apocalyptic number.

It is an amenable number.

1350483933 is a deficient number, since it is larger than the sum of its proper divisors (450161315).

1350483933 is an equidigital number, since it uses as much as digits as its factorization.

1350483933 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450161314.

The product of its (nonzero) digits is 116640, while the sum is 39.

The square root of 1350483933 is about 36748.9310456780. The cubic root of 1350483933 is about 1105.3414948831.

The spelling of 1350483933 in words is "one billion, three hundred fifty million, four hundred eighty-three thousand, nine hundred thirty-three".